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How we do this one there more than one answer

How we do this one there more than one answer-example-1
User Mlykotom
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1 Answer

1 vote

Solution:

Given;


\tan^2x-(1)/(3)=0,[0,2\pi)

Thus;


\begin{gathered} \tan^2x=(1)/(3) \\ \\ \tan x={\pm}\sqrt{(1)/(3)} \end{gathered}

Thus;


\begin{gathered} x=\tan^(-1)((1)/(3)) \\ \\ x=(\pi)/(6),(7\pi)/(6) \\ \\ x=\tan^(-1)(-(1)/(3)) \\ \\ x=(5\pi)/(6),(11\pi)/(6) \end{gathered}

So, the solution is;


x=(\pi)/(6),(7\pi)/(6),(5\pi)/(6),(11\pi)/(6)

User Acjay
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