Question

a Speeding Bullet The fastest commercially available rifle bullet claims a muzzle velocity of 4225 ft>s. How far (in meters) can this bullet travel in 5.0 ms?

Answer 1

21.125 m

Step-by-step explanation

Assuming the bullet has a constant velocity of 4225 ft/s when fired, the distance it travels in t seconds is:

`\begin{gathered} v=(d)/(t) \\ d=v\cdot t \end{gathered}`

If we want to find the distance in 5 ms, we have to multiply it by the velocity but we have to use the same units:

`5ms=0.005s`

The distance is then:

`d=4225(ft)/(s)\cdot0.005s=21.125m`