Answer:
The magnitude of the vector is 5.
Step-by-step Explanation:
The magnitude of a vector |v| can be found using the Pitagoras theorem, according to the figure below:
The magnitude can be calculated as:
![|v|=\sqrt[]{x^2+y^2}](https://img.qammunity.org/2023/formulas/mathematics/high-school/pjcf3b9i3j2vturzy5hhkadtuhvnigt20e.png)
In this exercise,
x = -3
y = 4
So,
![\begin{gathered} |v|=\sqrt[]{3^2+4^2} \\ |v|=\sqrt[]{9+16} \\ |v|=\sqrt[]{25} \\ |v|=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/1h4qhzq2xkt2khzdicbjf9yuyu0x6h3ifu.png)
The magnitude of the vector is 5.