First let's draw a sketch of the question, using the points A, B and C to make the triangle and points D and E to create the line parallel to the third side:
Since the segments DE and BC are parallel, so the corresponding angles ADE and ABC are congruent.
Also, angle A is common to both triangles ADE and ABC.
Since we have two pairs of congruent angles, we can prove that the triangles ADE and ABC are similar by case AA (angle-angle).
Therefore the answer is YES.