1.6) given
mass of car= 2m
mass of toy trailer = m
we know,
the formula of force is mass × acceleration
Result,
T=ma
1.7) let, the mass of mercury is m₁
the radius of mercury is r₁
given,
the mass of Neptune is 300m₁
the radius of Neptune is 10r₁
now we know that formula for the gravitation field is Gm/r²
where m is mass, G is gravitational constant, and r is the radius of the planet.
it is also given that the gravitation field on mercury is g
so,
![g=(Gm_1)/((r_(^1))^2)](https://img.qammunity.org/2023/formulas/physics/college/b8vdlw8x6tufm89rbdmbnj7cem3re967in.png)
now,
gravitation field on Neptune is,
![\begin{gathered} (G(300m_1))/((10r_1)^2) \\ \\ \Rightarrow(300)/(100)(Gm_1)/((r_1^)^2) \\ \\ \Rightarrow3\text{ g} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/vf9bp3ablls3tixm06jsf1p3za6g5lkciu.png)
result,
3g
1.8)
we know,
the gravity on the moon is 1/6th that of Earth
Result,
So option A is correct.