Question

Can you help me with my work

Answer 1

1. A

2.

`\begin{gathered} x^2-9^2=(x-9)(x+9) \\ x^2-7^2=(x-7)(x+7) \\ 4x^2-3^2=(4x-3)(4x+3) \end{gathered}`

difference of squares problem can be factored as follows: a2 – b2 = (a + b)(a – b) or (a – b)(a + b). So, all you need to do to factor these types of problems is to determine what numbers squares will produce the desired results.

3.

`(x-5)(x+5)=x^2-5^2`

4.

`(x+1)^2=x^2+2x+1`

they are different case of multiplication because the first one is a factoring case and this one is newton's binomial