You have 3 moles of Mn3(PO.)4. How many grams are present?

asked Aug 23, 2023 81.1k views

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In this question, we have to find the mass of Mn3(PO4)4, we will be using the molar mass of the compound, which is 544.7g/mol

544.7g = 1 mol

x grams = 3 moles

x = 1634 grams of Mn3(PO4)4

Pete Houston answered Aug 27, 2023

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