Question

im supposed to solve this, but im first supposed to convert the bases to be the same and thats what im struggling with​

Answer 1

9514 1404 393

Answer:

1

Explanation:

From your knowledge of multiplication tables, you know that ...

8 = 2×2×2 = 2³

4 = 2×2 = 2²

so the problem can be rewritten as ...

`(8^4)/(4^6)=((2^3)^4)/((2^2)^6)=(2^(3\cdot4))/(2^(2\cdot6))=(2^(12))/(2^(12))=\boxed{1}`

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The applicable rule of exponents is ...

(a^b)^c = a^(bc)

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Alternate solution

You could use 8^2 = 64 and 4^3 = 64. Then this is (8^2)^2/(4^3)^2 = 64^2/64^2, where the common base is 64, not 2.