Question

A and B are two events in an experiment where P(A) = 0.6 and P(A∩B)=0.2.  Find P(B | A).

Answer 1

`P\mleft(B|A\mright)\text{ = }(1)/(3)`

Here, we are to find the probability of event B given event A

What we will use here is the Bayes' theory of conditional probability

Mathematically, we can have this as;

`\begin{gathered} P(B|A)\text{ = }\frac{P(A\text{ n B)}}{P(A)} \\ =\text{ }(0.2)/(0.6)\text{ = }(1)/(3) \end{gathered}`