Question

A man pushes a lawn mower on a level lawn with a force of 192 N. If 28% of this force is directed forward, how much work is done by the man in pushing the mower 7.2 m? answer with:___J

Answer 1

Given:

The man pushes the lawn mower with the force of

`F=192\text{ N}`

The forward-directed force is,

`28\text{ \%}`

The mower moves

`d=7.2\text{ m}`

To find:

The work done by the man

Step-by-step explanation:

The force in the forward direction is,

`\begin{gathered} F^(\prime)=F*28\text{ \%} \\ =192*(28)/(100)\text{ N} \\ =53.8\text{ N} \end{gathered}`

The work in moving the lawn mower is,

`\begin{gathered} W=F^(\prime)d \\ =53.8*7.2 \\ =387.4\text{ J} \end{gathered}`

Hence, the work done by the man in pushing the mower 7.2 m is 387.4 N.