Question

I need help with this practice Having trouble with it

Answer 1

Answer: We have to solve the sinusoidal equation on the Interval [0,2pi):

`-8\cos (x)=3`

Simplifying gives:

`\cos (x)=-(3)/(8)\Rightarrow(1)`

Taking the functional Inverse gives:

`x=\cos ^(-1)(-(3)/(8))`

The answer is:

`x\approx1.955r\Rightarrow\lbrack0,2\pi)`