Question

Find the Area of the figure below, composed of a rectangle and onesemicircle, with another semicircle removed. Round to the nearesttenths place.

Answer 1

Area of semicircle is:

`A_(sc)=(\pi r^2)/(2)`

Area of rectangle is:

`A_r=\text{length }*\text{ width}`

Length = 13

Width = 12

Diameter of circle =12

`\begin{gathered} \text{Radius}=(d)/(2) \\ =(12)/(2) \\ =6 \end{gathered}`

Area of shape is:

`\text{Area}=\text{ rectangle area+semicircle area-othe semicircle area}`
`\begin{gathered} \text{Area}=(\text{length}*\text{ width)+}((\pi r^2)/(2))-((\pi r^2)/(2)) \\ =(13*12)+((\pi(6))/(2)^2)-((\pi(6)^2)/(2)) \\ =13*12 \\ =156 \end{gathered}`

Area of shape is 156.