Question

3. The perimeter of a rectangle garden is 60 feet. If the length of the garden is twice its width find the length and width of the garden,

Answer 1

The perimater of the garden is P=60 feet

The length is twice its width.

Let "x" represent the measure of the width of the garden, then:

w=x

l= 2x

The formula to calculate the perimeter is:

`P=2w+2l`

Replace it with the determined equalities, and you get that the perimeter of the garden is equal to:

`60=2x+2(2x)`

From this expression you can calculate the value of x

`\begin{gathered} 60=2x+4x \\ 60=6x \\ (6x)/(6)=(60)/(6) \\ x=10 \end{gathered}`

w=x=10 feet

l=2x=2*10=20 feet

The width of the garden is w=10 feet and the length of the garden is l=20 feet