Given that:
- Amber can peel this amount of potatoes:
![10(1)/(2)\text{ }potatoes](https://img.qammunity.org/2023/formulas/mathematics/college/qnlfo77bwi80tdwkcumo1ocyddqyqgr6lp.png)
- And she can peel them in this time:
![(1)/(3)\text{ }hour](https://img.qammunity.org/2023/formulas/mathematics/college/lqzh21g1b23lpu32zmur10d3c0c3p0l1a4.png)
You can determine that the Unit Rate is the number of potatoes she can peel per hour.
Since the number of potatoes is given as a Mixed Number, you can convert it to an Improper Fraction as follows:
1. Multiply the Whole Number part by the denominator.
2. Add the Product to the numerator.
3. The denominator does not change.
Then:
![10(1)/(2)=((10\cdot2)+1)/(2)=(20+1)/(2)=(21)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/ltqi1d24slmi2neltmqslbiryqfcudq084.png)
Now you can set up that:
![Unit\text{ }Rate=\frac{(21)/(2)\text{ }potatoes}{(1)/(3)\text{ }hour}](https://img.qammunity.org/2023/formulas/mathematics/college/rz0d1zh9ewv9eqhqy1zd44qlbr1jg0vwxl.png)
Solving the Division, you get:
![\begin{gathered} Unit\text{ }Rate=(21\cdot3)/(2\cdot1)(potatoes)/(hour) \\ \\ Unit\text{ }Rate=(63)/(2)(potatoes)/(hour) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x5txgelut71gva9ckrwpluhdb5gdxf7jw7.png)
Hence, the answer is:
![Unit\text{ }Rate=(63)/(2)(potatoes)/(hour)](https://img.qammunity.org/2023/formulas/mathematics/college/y2u6drmtof83e9hiosexrlmn785ko21gy4.png)