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Write an equation for a line perpendicular to Y=-4x-4 and passes through the points(12,5)

User Degill
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2 Answers

13 votes

Hi!

I can help you with joy!

An equation for a line looks like so: y=mx+b

m = slope and b = y-intercept

Guide to Finding Equations of Lines:

Recall that perpendicular lines have slopes that


\text{are opposite reciprocals}.

Clarification: We take the slope, flop it over, and change its sign:


\tt{y=-4x-4}\\Perpendicular:\\y=(1)/(4) (Slope)

Equation:

(Point-Slope Form: y-y1=m(x-x1)

y-5=1/4(x-12)

y-5=1/4x-3

y=1/4x-3+5

y=1/4x+2 (Answer)

Hope it helps!

~Misty~

User Joneshf
by
8.4k points
3 votes

Answer:

y =
(1)/(4) x + 2

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 4x - 4 ← is in slope- intercept form

with slope m = - 4

Given a line with slope m then the slope of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/(-4) =
(1)/(4) , then

y =
(1)/(4) x + c ← is the partial equation

to find c substitute (12, 5 ) into the partial equation

5 = 3 + c ⇒ c = 5 - 3 = 2

y =
(1)/(4) x + 2 ← equation of perpendicular line

User JBE
by
8.1k points

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