Question

21) Given the balanced equation4Fe (s) + 3O2 (g) --> 2Fe2O3 (s)When 26.16 g of O2 react with excess Fe, and this is the only reaction which occurs, theoretically how many grams of Fe2O3 should be produced? Keep the answer with 2 decimal places.

Answer 1

Step 1

The reaction:

4Fe (s) + 3O2 (g) ===> 2Fe2O3 (s) (completed and balanced)

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Step 2

Information provided:

The limiting reactant, 26.16 g O2

Information needed: the molar masses of:

O2) 32.0 g/mol

Fe2O3) 160 g/mol

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Step 3

Theoretically means: the mass of Fe2O3 is calculated by the reaction

4Fe (s) + 3O2 (g) ===> 2Fe2O3 (s)

3 x 32 g O2 -------- 2 x 160 g Fe2O3

26.16 g O2 ---------- X

X = 26.16 g O2 x 2 x 160 g FeO3/3 x 32 g O2 = 87.20 g Fe2O3

Answer: 87.20 g Fe2O32