Given data
*The given height of the roof above the ground is h = 12.2 m
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The formula for the time taken by the ball to reach the ground is given as
![t=\sqrt[]{(2h)/(g)}](https://img.qammunity.org/2023/formulas/physics/college/bf4ls0n97d0h2dgi9qjnvaysom2eznam6b.png)
Substitute the known values in the above expression as
![\begin{gathered} t=\sqrt[]{(2*12.2)/(9.8)} \\ =1.58\text{ s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/afc1n2991iscmvd2i3wl7l2b74qnin6pzm.png)
Hence, the time taken by the ball to reach the ground is t = 1.58 s