Question

The mole fraction of NaCl in anaqueous solution is 0.132. Howmany moles of NaCl are present in1 mole of this solution?Molar MassNaCl: 58.44 g/molH2O: 18.016 g/mol

Answer 1

The mole fraction of a solution is the number of moles of NaCl, the solute, divided by the total number of moles of solution:

`f=\frac{n_(NaCl)}{n_{\text{solution}}}`

If we have 1 mol of solution, then:

`n_{\text{solution}}=1mol`

And the mole fraction is given, so:

`f=0.132`

So, to calculate the number of moles of NaCl, we can solve for it and input the given values:

`\begin{gathered} f=\frac{n_(NaCl)}{n_{\text{solution}}} \\ n_(NaCl)=f\cdot n_{\text{solution}} \\ n_(NaCl)=0.132\cdot1mol \\ n_(NaCl)=0.132mol \end{gathered}`

So, there are 0.132 moles of NaCl in the solution.