Question

Show the equation in slope-intercept form that represents a line that has a slope of 1/3 and passes through (12, -6)?

Answer 1

y = 1/3x - 10

Explanation:

→ Write gradient in form y = mx + c

y = 1/3x + c

→ Substitute in 12 and -6

-6 = 4 + c

→ Solve for c

c = -10

→ Rewrite into y = mx + c format

y = 1/3x - 10

Answer 2

Hi!

I can help you with joy!

First of all, we are given the slope and a point that the line passes through.

So, we can write the line's equation in Point-Slope Form:

`\text{y-y1=m(x-x1)}`

Plug in the values:

`\text{y-(-6)=m(x-12)}`

`\tt{y+6=(1)/(3) (x-12)}`

`\tt{y+6=(1)/(3) x-4`

Move 6 to the right:

`\tt{y=(1)/(3) x-4-6}\\\tt{y=(1)/(3) x-10`

Hope it helps!

Ask me if you have any doubts.

• Enjoy Your Day/Night!

~Silent~