The standard form of equation of a circle is given by;
(x-a)² + (x-b)² = r²
where (a, b) is center of the circle and r is the radius
The question given is;
(x-6)² + y² = 136
This can be re-written as;
(x-6)² + ( y-0)² = 136
comparing with the standard equation;
(6, 0) is the center of the circle
r² = 136
take the square root of both-side
r= 11. 66
radius = 11. 66