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Suppose that y varies directly as the square root of x, and that y = 37 when x = 121. What is y when x = 196? Round your answer to two decimal places if necessary.

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y = k√x

Since y varies directly ast the square root of x, it has a constant k.

y = 37 when x = 121

Replace to find k:

37=k√121

37=k11

37/11 =k

So, when x = 196

y = 37/11 √196

y = 37/11 (14)

y= 47.09

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