Question

I know the first part of the question is solve by54 = N x 120N = 45%How do I find the percent of incorrect answers?

Answer 1

To determine the percent of incorrect answers:

Out of 120 trigonometry test question, 54 was answered correctly:

Let the number of question with incorrect answer be 120 - 54 = 66

`\begin{gathered} x\text{ \% 0f 120 =66} \\ (x)/(100)\text{ x 120 = 66} \\ (120x)/(100)=66 \\ 120x=6600 \\ \text{divide both side by 120} \\ x=(6600)/(120) \\ x=55\text{ \%} \end{gathered}`

Hence she answered 55 % incorrectly