Question

Don't know what to so I'm in 9th grade.Solve for x.

Answer 1

Given:

`y=-2(x+7)^2+13`

Let's solve the equation for x.

• Re-arrange the equation:

`-2(x+7)^2+13=y`

• Subtract 13 from both sides of the equation:

`\begin{gathered} -2(x+7)^2+13-13=y-13 \\ \\ -2(x+7)^2=y-13 \end{gathered}`

• Divide both sides by -2:

`\begin{gathered} (-2(x+7)^2)/(-2)=(y-12)/(-2) \\ \\ (x+7)^2=(y-13)/(-2) \end{gathered}`

• Take the square root of both sides:

`\begin{gathered} √((x+7)^2)=\sqrt{(y-13)/(-2)} \\ \\ x+7=\sqrt{(y-13)/(-2)} \end{gathered}`

• Subtract 7 from both sides of the equation:

`\begin{gathered} x+7-7=\sqrt{(y-13)/(-2)}-7 \\ \\ x=\sqrt{(y-13)/(-2)}-7 \end{gathered}`

ANSWER:

`x=\sqrt{(y-13)/(-2)}-7`