Question

consider the graph of f(x) = 5^x +1. Explain how to find the average rate of change between x=0 and x=4 what is the average rate of change?

Answer 1

`\begin{gathered} \text{Average rate of change = }(f\mleft(4\mright)-f\mleft(0\mright))/(4-0)_{} \\ \\ Si\text{nce x = 0 and x = 4} \\ f(x)=5^x+1 \\ f(4)=5^4+1 \\ f(4)=625+1=626 \\ f(0)=5^0+1 \\ f(0)=1+1=2 \\ \\ \text{Average rate of change = }(f(4)-f(0))/(4-0) \\ \\ \text{Average rate of change = }(626-2)/(4-0) \\ \\ \text{Average rate of change = }(624)/(4) \\ \\ \text{Average rate of change = }156 \end{gathered}`