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Solve the system by substitution. x—5=y -3x—y= -19

User SkaveRat
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\begin{gathered} x-5=y \\ -3x-y=-19 \\ x-y=5\ldots\ldots\ldots\ldots.......(1) \\ -3x-y=-19\ldots.\ldots\ldots....(2) \\ x=5+y \\ -3(5+y)-y=-19 \\ -15-3y-y=-19 \\ -15-4y=-19 \\ -4y=-19+15 \\ -4y=-4 \\ y=(-4)/(-4) \\ y=1 \\ x-5=y \\ x-5=1 \\ x=1+5 \\ x=6 \end{gathered}

User Bharat
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