Question

Container A and container B have leaks. Container A has 800 ml of water and is leaking 6 ml per minute.Container B has 1000 ml and is leaking 10 ml per minute.How many minutes (m) will it take for the two containers to have the same amount of water ?What is Container A Expression =What is Container B Expression =Explain what your solution mean for the containers?

Answer 1

Let t represent the time in minute after which the container will have same amount of water

800 - 6t = 1000 - 10t

collect like term

-6t + 10t = 1000 - 800

4t = 200

Divide both-side of the equation by 4

t= 50 minutes