181k views
0 votes
Hello!! I’m amy, I need help on this I am in the 6th grade and I’m having trouble

Hello!! I’m amy, I need help on this I am in the 6th grade and I’m having trouble-example-1
User Isaias
by
6.1k points

1 Answer

3 votes

Area of the triangle is:


\text{Area}=(1)/(2)\text{base}* height

Base of triangle is 8 and height of the triangle is 6 so the area of triangle is:


\begin{gathered} \text{Area of first triangle=}(1)/(2)*8*6 \\ =24 \\ \text{Area of second triangle is =}(1)/(2)*8*6 \\ =24 \end{gathered}

Area of rectangle:


\text{Area }=\text{length}* width

For first rectangle length is 10 and width is 5 so area is:


\begin{gathered} A_1=\text{length}* width \\ =10*5 \\ =50 \end{gathered}

For second rectangle length is 8 and width is 5 so area is:


\begin{gathered} A_2=\text{length}* width \\ =8*5 \\ =40 \end{gathered}

For last rectangle length is 6 and width is 5 then:


\begin{gathered} A_3=\text{length}* width \\ =6*5 \\ =30 \end{gathered}

So area is:


\begin{gathered} \text{Area =24+24+50+40+30} \\ =168unit^2 \end{gathered}

User Shrirang
by
5.7k points