Question

580 nm light shines on a double slitwith d= 0.000125 m. What is theangle of the first bright interferencemaximum (m= 1)?(Remember, nano means 10-9.)(Unit = deg)

Answer 1

0.266 degrees.

Step-by-step explanation:

To find the angle of the first bright interference, we will use the following equation

`m\lambda=d\sin\theta`

So, replacing

m = 1

λ = 580 nm = 580 x 10^(-9) m

d = 0.000125 m

we get:

`1(580*10^(-9))=0.000125\sin\theta`

Then, solve for θ

`\begin{gathered} 580*10^(-9)=0.000125\sin\theta \\ \\ (580*10^(-9))/(0.000125)=\sin\theta \\ \\ 4.64*10^(-3)=\sin\theta \\ \theta=\sin^(-1)(4.64*10^(-3)) \\ \theta=0.266 \end{gathered}`

Therefore, the answer is 0.266 degrees.