Question

based on A poll 43% of adults believe in reincarnation. assume that 6 adults are randomly selected. find p ( exactly 6 of the 6 believe in reincarnation)

Answer 1

Given data:

P = 43% = 43/100 = 0.43 p = probability that adults believe in reincarnation

q = 1 - p = 1 - 0.43 = 0.57 q = probability that adults did'nt believe in reincarnation

`\begin{gathered} =^nC_rp^rq^{n\text{ - r}}^{} \\ n\text{ = 6} \\ r\text{ = 6} \\ =^6C_6(0.43)^{6^{}}(0.57)^(6-6) \\ ^6C_6\text{ = 1} \\ =\text{ 1 }*(0.43)^6(0.57)^0 \\ =\text{ 1 x 0.00632 }*\text{ 1} \\ =\text{ 0.00632} \end{gathered}`

Final answer

Probability = 0.00632