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The bullseye of an archery target has a radius of 3 inches. The entire target has a radius of 9 inches find the area of the target outside of the bullseye

User Besen
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We are asked to find the area of the target outside of the bullseye.

Recall that the area of a circular archery target is given by


A=\pi r^2

Where r is the radius.

The bullseye has a radius of 3 inches.

The area of the bullseye is given by


A_{}=\pi r^2=\pi\cdot3^2=9\pi\; in^2

The entire target has a radius of 9 inches.

The area of the entire target is given by


A_{}=\pi r^2=\pi\cdot9^2=81\pi\; in^2

Subtract the area of the bullseye from the entire target area to find the area of the target outside of the bullseye.


A=81\pi-9\pi=72\pi\; =226.1\; in^2

Therefore, the area of the target outside of the bullseye is 226.1 in^2

Option a. is the correct answer.

User Meneghino
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