Find the length of the altitude of an isosceles triangle with a 64° vertex angle and a base 48 cm long. Round your answer to the nearest tenth.

asked Sep 20, 2023 111k views

4 votes

by Ziggy

5.6k points

Please log in or register to add a comment.

4 votes

Therefore,

$\begin{gathered} \tan (32^0)=(24)/(h) \\ \text{thus} \\ h=(24)/(\tan(32^0))=38.4\operatorname{cm} \end{gathered}$

Therefore the length of the altitude is 38.4cm

Soroush Gholamzadeh answered Sep 26, 2023

4.9k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.7m questions

7.5m answers