Question

A cylinder contains 28.0 L of oxygen gas at a pressure of 1.7 atm and a temperature of 292 K. How many moles of gas are in the cylinder?

Answer 1

We know that:

- Pressure of the oxygen gas = 1.7 atm

- Volume of the oxygen gas = 28.0 L

- Temperature of the oxygen gas = 292 k

In order to find the number of moles of has in the cylinder we must use the ideal gas equation

`PV=nRT`

Where,

- P: Pressure

- V: Volume

- T: Temperature

- n: number of moles

- R: Universal gas constant

Since we must find the number of moles we need to solve the formula for n

`n=(PV)/(RT)`

Finally, we must replace the values in the formula for n

`n=\frac{1.7\text{atm}\cdot28.0L}{0.08206(L\cdot atm)/(mol\cdot k)\cdot292k}`
`n=1.9865\text{mol}`