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(x^2÷x)^2(-4)^2-x x=5

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Given:


\begin{gathered} ((x^2)/(x))^2(-4)^2-x \\ \\ x=5 \end{gathered}

To solve the expression when x = 5, substitute x for 5 and evaluate.

We have:


\begin{gathered} ((5^2)/(5))^2(-4)^2-5 \\ \\ =((25)/(5))^2(16)-5 \end{gathered}

Solving further:


\begin{gathered} =(5)^2(16)-5 \\ \end{gathered}
undefined

User Junuxx
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