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A 10 kg box is being pushed to the right with 10.0 N of force while experiencing 8.0 N of friction force. What is the sum of all of the forces on the box?

User Fei Xue
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1 Answer

1 vote

Given information:

Applied force,


F=10.0\text{ N}

Friction force,


f=8.0\text{ N}

Schematic diagram:

The net force acting on the box is given as,


F_(net)=F-f

Substituting all known values,


\begin{gathered} F_(net)=(10.0\text{ N})-(8.0\text{ N}) \\ =2.0\text{ N} \end{gathered}

Therefore, the sum of all of the forces on the box is 2.0 N.

A 10 kg box is being pushed to the right with 10.0 N of force while experiencing 8.0 N-example-1
User Angad Tiwari
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