C)
Step-by-step explanation
the weigth of a mass is given by the formula
![\begin{gathered} \text{Weigth(w)}=\text{mass(m)}\cdot(\text{acceleration due to gravity)(g)} \\ w=mg \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/k0iq12thwl3expvx9re6tdj3vpwly5ln04.png)
we already now, that the acceletion of gravity is bigger in the earth than in the moon ( because it depens on the mass, and the earth has very more mass than the moon)
so, for the moon we have
![\begin{gathered} w_m=m_m\cdot g_m \\ \text{isolate m}_m \\ m_m=(w_m)/(g_m) \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/4qbbuntrykgt2f0k5a6lce71qvv7w924kd.png)
now, when the mass in in the earth
![\begin{gathered} w_e=m_e\cdot g_e \\ m_e=(w_e)/(g_e) \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/bbsna99v9kav232pl2iemmtf05bl99bgkg.png)
now, if we compare the masses ,equal ratios
![\begin{gathered} m_m?m_e \\ (w_m)/(g_m)=(w_e)/(g_e) \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/envsr3opxbksuyulbx8oykdwf937ouck1n.png)
we can see a ration of the weigth and g, as w depens on g, we can replace
![\begin{gathered} (m_m\cdot g_m)/(g_m)=(m_e\cdot g_e)/(g_e) \\ m_m=m_e \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/fipghwd6w3zqcnmnao09qhzzrctkq4ijfq.png)
we can conclude mass is the amount of matter in an object and does not change with location
If an object is moved to a location of greater gravitational force, , its weight will increase, but mass still remains the same.
so, the answer is
![C)m_m=m_e](https://img.qammunity.org/2023/formulas/physics/college/l3iw58xzqy76v7rb6z4uq7hznrdyf5m3bj.png)
I hope this helps you