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Can someone help me here please!thank you so much​

Can someone help me here please!thank you so much​-example-1

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Answer:

  1. x² +y² -6x -4y -3 = 0
  2. x² +y² -10x +4y = 0

see the attachment for graphs of these

Explanation:

You want the general form equation and graph of circles with the given center and (1) radius 4, and (2) through point (0, 0).

Equation of a circle

The standard-form equation of a circle with radius r and center (h, k) is ...

(x -h)² +(y -k)² = r²

The general form equation will be a rearrangement of this:

x² +y² -2hx -2ky +(h² +k² -r²) = 0

1.

The center is (h, k) = (3, 2), and the radius is r = 4. Put these values in the above equation:

(x -3)² +(y -2²) = 4² . . . . standard form

x² +y² -6x -4y -3 = 0 . . . . general form

2.

For this one, you don't know the radius, but you know a point that satisfies the equation. Using the point coordinates for x and y, you can find the necessary radius (squared).

The center is (h, k) = (5, -2), and point (x, y) = (0, 0) satisfies the equation.

(x -5)² +(y -(-2))² = (0 -5)² +(0 -(-2))² = 25 +4

(x -5)² +(y +2)² = 29 . . . . standard form

x² +y² -10x +4y = 0 . . . . general form

Can someone help me here please!thank you so much​-example-1
User Spassig
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