Solve each equation first and then choose the appropiate statement.
Equation 1
![|5x-6|=-41](https://img.qammunity.org/2023/formulas/mathematics/college/h7tnyojh4djh38i8xfgdd61tqagio10ggo.png)
Since the absolute value of a number is always greater than 0 and -41<0, then this equation has no solutions.
Equation 2
![\begin{gathered} |7x+13|=27 \\ \Rightarrow7x+13=\pm27 \\ \Rightarrow7x=\pm27-13 \\ \Rightarrow x=(\pm27-13)/(7) \\ \Rightarrow x_1=(27-13)/(7)=(14)/(7)=2 \\ \Rightarrow x_2=(-27-13)/(7)=(-40)/(7) \\ \therefore x_1=2,x_2=-(40)/(7) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/glhap2uynqnsxco1tqlmowhxgh1xxosid2.png)
We can see that Equation 1 has 0 solutions and Equation 2 has 2 solutions.
Therefore, equation 2 has more solutions than equation 1.