The equation of a line is given as:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
where m is the slope and (x1,y1) is a point through the line. The slope is given as:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
In this case we have the points (since 1986) (2,50200) and (14,63400), then the slope is:
![\begin{gathered} m=(63400-50200)/(14-2) \\ m=(13200)/(12) \\ m=1100 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8phk1egfauj55x6stwm2anc20smj3nmmxf.png)
Plugging the values we have the equation:
![\begin{gathered} y-50200=1100(x-2) \\ y-50200=1100x-2200 \\ y=1100x+50200-2200 \\ y=1100x+48000 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/otp7sal8dqf3ej8lea784mscsy3lcn0sut.png)
Therefore the equation we are looking for is:
![y=1100x+48000](https://img.qammunity.org/2023/formulas/mathematics/college/2pvddgfjqvhop6z4zcn6raz0wef51b38rz.png)