Question

Polygon KLMN is drawn with vertices at K(0, 0), L(5, 2), M(5, −5), N(0, −3). Determine the image vertices of K′L′M′N′ if the preimage is rotated 180° clockwise. K′(0, 0), L′(−2, 5), M′(5, 5), N′(3, 0) K′(0, 0), L′(2, −5), M′(−5, 5), N′(−3, 0) K′(0, 0), L′(−2, 5), M′(5, 5), N′(3, 0) K′(0, 0), L′(−5, −2), M′(−5, 5), N′(0, 3)

Answer 1

K′(0, 0), L′(−2, 5), M′(5, 5), N′(3, 0)

Step-by-step explanation:

Answer 2

`D`

Step-by-step explanation:

Here, we want to get the image of the vertices of the polygon KLMN after rotating 180 degrees clockwise

If we rotate 180 degrees clockwise, we have it that:

`(x,y)\text{ becomes \lparen-x,-y\rparen}`

Applying this rule, we have it that:

`\begin{gathered} K^\text{ ' = \lparen0,0\rparen} \\ L\text{ ' = \lparen-5,-2\rparen} \\ M^\text{ ' = \lparen-5,5\rparen} \\ N\text{ ' = \lparen0,3\rparen} \end{gathered}`

Thus, we have the correct answer choice option as D