Question

O Given AXPS = ADNF, find the values of x and y.

Answer 1

Since both triangles XPS and DNF are congruent, we have the following equations:

`\begin{gathered} 4y-3=57 \\ 17x+3=54 \end{gathered}`

in the first equation, solving for y we get:

`\begin{gathered} 4y-3=57 \\ \Rightarrow4y=57+3=60 \\ \Rightarrow y=(60)/(4)=15 \\ y=15 \end{gathered}`

then, for the second equation, we have:

`\begin{gathered} 17x+3=54 \\ \Rightarrow17x=54-3=51 \\ \Rightarrow x=(51)/(17)=3 \\ x=3 \end{gathered}`

therefore, y = 15 and x = 3