ANSWER
7/15
Step-by-step explanation
We can see that there are 6 time slots. It is said that the first five are 50 minutes long and the 6th is 75 minutes long.
Gerald has a class on the 2nd slot, another on the 3rd slot and one more in the 6th slot. Therefore in total he's scheduled for:
![50+50+75=175](https://img.qammunity.org/2023/formulas/mathematics/high-school/c6c5un2qdfahe80870066ftmb10mv7w1pt.png)
175 minutes of class.
We have to see how many minutes there are between 8 AM and 2:15 PM. We can add first the hours: from 8am to 12pm there are 4 hours. Then from 12pm to 2 pm there are 2 more hours. In total that's 6 hours which in minutes is:
![6*60=360](https://img.qammunity.org/2023/formulas/mathematics/high-school/rc937itww7ngt69v2cbau8zn7hxsgq40u6.png)
But we have to add the last 15 minutes:
![360+15=375](https://img.qammunity.org/2023/formulas/mathematics/high-school/1ybd6k9iwr2kyojmxcq4747kitgs0x4cs7.png)
In summary, between 8AM and 2:15 PM there are 375 minutes, from which 175 minutes are the one Gerald has classes. To find the fraction we have to put 175 in the numerator and 375 in the denominator:
![(175)/(375)](https://img.qammunity.org/2023/formulas/mathematics/high-school/xq2q8wmk8nt7va0wck6iejlvc32zne2yvf.png)
And simplify:
![\begin{gathered} \text{ divide both num and den by 25:} \\ (7)/(15) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/twqup7dgjmmdhrwet019ii0bg97b436kis.png)
So Gerald is scheduled for class 7/15 of the time between 8AM and 2:15 PM