Three jelly donuts and two glazed donuts cost $1.30. Thefore we can write the equation

Where "x" is the cost of one jelly donut and y is the cost of one glazed donut.
And one jelly donuts cost .10 less than two glazed donuts. Then we can write the second equation

We can write that equation as

Now we have a system of equations

If we sum them we get

Now we have the value of x we can put it in one of our equations and solve for y

Therefore

The cost of one jelly doughnut is $0.3 and the cost of one glazed donut is $0.2