Question

A ball is traveling horizontally when it clears a volleyball net that is 1.5m high. What maximum {horizontal) speed (in m/s) can it have if it is to fall within 5 meters of the net? Please input your answers as positive values with two decimal places.

Answer 1

horizontal distance = 5 meteres

height = 1.5 meters

Therefore,

y component

`\begin{gathered} 0=1.5+(1)/(2)(-9.8)t^2 \\ 1.5=4.9t^2 \\ t^2=(1.5)/(4.9) \\ t=\sqrt[]{0.30612244898} \\ t=0.55328333517 \\ t=0.55\text{ s} \end{gathered}`

The maximum speed(horizontal) can be computed as follows

`\begin{gathered} S_x=ut \\ 5=0.55u \\ u=(5)/(0.55) \\ u=9.09090909091 \\ u=9.09\text{ m/s} \end{gathered}`

The maximum speed is the initial horizontal velocity of the x-axis.