Solution
For this case we can select two fractions less than 1, lets say:
![(a)/(b),(c)/(d)](https://img.qammunity.org/2023/formulas/mathematics/college/g5fsr1uvgutdc7pse7pgnyg9bjy6ijjiwc.png)
Where a
Then if we divide both fractions we have:
![((a)/(b))/((c)/(d))=(a\cdot d)/(b\cdot c)](https://img.qammunity.org/2023/formulas/mathematics/college/u28d2obza2tqan65ocjpgdbp7lduqm7kma.png)
From this we can use the fact that this fraction is less than 1 but is also higher than the original fractions following the priciple that the smaller a number is, the more of them can “fit” (divided) into a number.