Question

How many kilograms of phosphorous are in a sample containing 1.00E31 phosphorous atoms?

Answer 1

Answer:
`5.15* 10^5kg`

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

Putting in the values we get:

`\text{Number of moles}=(1.00* 10^(31))/(6.023* 10^(23))=0.166* 10^(8)moles`

1 mole of phosphorous
`P` weighs = 31 g

Thus
`0.166* 10^8` moles of phosphorous
`P` weigh=
`(31)/(1)* 0.166* 10^8=5.15* 10^8g=5.15* 10^5kg`