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2. By hand, showing work (you can not use quad reg on your calculator), write the equation of the quadraticfunction that: passes through (4,3) and has x-intercepts of -1 and 5

User UserD
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1 Answer

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You have the following information about a quadratic function:

- The function passes through point (4,3)

- x-intercepts are -1 and 5

In order to determine which is the quadratic function, you take into account that general form of a quadratic function is:

f(x) = a(x - x1)(x - x2)

where x1 and x2 are the x-intercepts of f(x), given by:

x1 = -1

x2 = 5

By replacing the values of the x-intercepts you obtain:

f(x) = a(x - (-1))(x - 5)

f(x) = a(x + 1)(x - 5)

To find the value of a, you use the fact that the function passes trough point (4,3), that is, for x=4 anf f(x) = 3, you obtain:

3 = a(4 + 1)(4 - 5)

3 = a(5)(-1)

3 = -5a

-3/5 = a

Then, by replacing the value of a into the expression for f(x) you have:

f(x) = -3/5(x + 1)(x - 5)

User GTBebbo
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