The given fraction expression :
![(3)/(8)+(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/j54j3rya4jez9mxavat49cc7s333svabcn.png)
Since, from the property of fraction,
If the denominator of the set of fractions which are adding are equal then the numerator are sum up:
![(a)/(b)+(d)/(b)+(x)/(b)=(a+d+x)/(b)](https://img.qammunity.org/2023/formulas/mathematics/college/mqnnhnu8le9t5g183vnclztxsn1d6crgbu.png)
Since in the given expression the denominator ie equal to 8
thus, numerator will add
![\begin{gathered} (3)/(8)+(1)/(8)=(3+1)/(8) \\ (3)/(8)+(1)/(8)=(4)/(8) \\ \text{ Since, 4 divided 8 by 2} \\ (4)/(8)=(1)/(2) \\ (3)/(8)+(1)/(8)=(1)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ze0kefxhuvqb6ymqjhr3dnq0gpu0yndh3f.png)
Answer : 1/2