Question

4kg of water starts at 19 degrees Celsius and is heated to 89 Celsius. how much energy was needed to accomplish this

Answer 1

Q = m x c x Δt

Where:

m= mass = 4kg= 4000 g

c = specific heat = 4.186 J/g°C

Δt= temperature change = 89 - 19 = 70°C

Replacing:

Q = 4000 x 4.186 x 70° = 1,172,080 J