Question

How many grams of Kl are in 5.30x10^22 molecules of potassium iodide(Kl)?

Answer 1

14.6 g

Step-by-step explanation

Given:

Number of molecules of KI = 5.30 x 10²² molecules

What to find:

The grams of KI present in 5.30 x 10²² molecules.

Step-by-step solution:

Step 1: Convert the moles of KI to moles using Avogadro's number.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules

Therefore, the moles of KI in 5.30 x 10²² molecules will be

`\frac{5.30*10²²\text{ }molecules}{6.022*10²^3\text{ }molecules}*1\text{ }mol\text{ }KI=0.088\text{ }mol\text{ }KI`

Step 2: Use the mole formula to determine the mass of Ki in 0.088 mol KI.

Note: The molar mass of KI = 166 g/mol

`\begin{gathered} Mole=\frac{Mass}{Molar\text{ }mass} \\ \\ \Rightarrow Mass=Mole* Molar\text{ }mass \\ \\ Mass=0.088\text{ }mol*166\text{ }g\text{/}mol \\ \\ Mass=14.608\text{ }g\approx14.6\text{ }g \end{gathered}`

Therefore, 14.6 g of KI are in 5.30 x 10²² molecules of potassium iodide(Kl)