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Given: The base of the pyramid is a regular octagon.2514Find the lateral area of the pyramid.67270013441400

Given: The base of the pyramid is a regular octagon.2514Find the lateral area of the-example-1
User DavidL
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1 Answer

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From the given values for the two side of triangles in the side of the present pyramid, we can do as follows:

We are going to use the Pythagorean theorem to find the height of this triangle.


\begin{gathered} h^2+7^2=25^2 \\ h^2=625-49=576 \\ h=24 \end{gathered}

Now, we can use the values for the base and height of the triangle that is one of the sides of the pyramid to calculate its area:


\begin{gathered} A_{\text{triangle}}=(b* h)/(2) \\ A_{\text{triangle}}=(24*14)/(2)=168 \end{gathered}

And because the pyramid has 8 sides with the same geometry and size, all we need now is multiply this value by 8.


\begin{gathered} A_{\text{lateral}}=8* A_(triangle) \\ A_{\text{lateral}}=8*168 \\ A_{\text{lateral}}=1,344 \end{gathered}

From this, we can say that the answer is 1,344

Given: The base of the pyramid is a regular octagon.2514Find the lateral area of the-example-1
User Kaysush
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